Answer:
Hank had a z-score of -1.375.
Jane had a z-score of -2.39.
Jane had the better year relative to their peers, due to her lower z-score.
Explanation:
Z-score:
In a set with mean
and standard deviation
, the zscore of a measure X is given by:
![Z = (X - \mu)/(\sigma)](https://img.qammunity.org/2022/formulas/mathematics/college/bnaa16b36eg8ubb4w75g6u0qutzsb68wqa.png)
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
Hank:
ERA of 3.36. For the males, the mean ERA was 4.449 and the standard deviation was 0.792. This means that we have to find Z when
. So
![Z = (X - \mu)/(\sigma)](https://img.qammunity.org/2022/formulas/mathematics/college/bnaa16b36eg8ubb4w75g6u0qutzsb68wqa.png)
![Z = (3.36 - 4.449)/(0.792)](https://img.qammunity.org/2022/formulas/mathematics/college/6r9q9zxm6tuofzftmyv6p0864j9uoabc57.png)
![Z = -1.375](https://img.qammunity.org/2022/formulas/mathematics/college/mgcj1ekhqyyif4etsmnmltlzjfqan8j5f7.png)
Hank had a z-score of -1.375.
Jane
ERA of 3.49. For the females, the mean ERA was 5.091 and the standard deviation was 0.669. This means that we have to find Z when
. So
![Z = (X - \mu)/(\sigma)](https://img.qammunity.org/2022/formulas/mathematics/college/bnaa16b36eg8ubb4w75g6u0qutzsb68wqa.png)
![Z = (3.49 - 5.091)/(0.669)](https://img.qammunity.org/2022/formulas/mathematics/college/4ynaskliomo2r6pjwp2p4tdzdoineaumfy.png)
![Z = -2.39](https://img.qammunity.org/2022/formulas/mathematics/college/swpnim9nztxh1iiagsatitzr88mcb1y403.png)
Jane had a z-score of -2.39.
Which player had the better year relative to their peers, Hank or Jane
Low ERA is good, high is bad. This means that whoever had the lower z-score had the better year, and in this case, it's Jane