Question

AB=[ −4 −6 ​ 4 3 ​ ][ 3 −4 ​ 2 −1 ​ ] First problem B, A, equals, open square bracket, begin matrix row 1, column 1, 3 row 1, column 2, 2 row 2, column 1, minus, 4 row 2, column 2, minus, 1 end matrix , close square bracket, open square bracket, begin matrix row 1, column 1, minus, 4 row 1, column 2, 4 row 2, column 1, minus, 6 row 2, column 2, 3 end matrix , close square bracket BA=[ 3 −4 ​ 2 −1 ​ ][ −4 −6 ​ 4 3 ​ ] Second problem

Answer 1

To find the product of two matrices, AB, multiply corresponding elements of the first row of matrix A with the corresponding elements of each column of matrix B and sum up the products. Repeat for all rows of matrix A.

Step-by-step explanation:

The given problem involves matrix multiplication. To find the product of two matrices, AB, we need to perform the following steps:

1. Multiply the corresponding elements of the first row of matrix A with the corresponding elements of each column of matrix B.
2. Sum up the products obtained in step 1 to get the first element of the resulting matrix.
3. Repeat steps 1 and 2 for all the rows of matrix A to obtain the complete product matrix AB.

Applying these steps to the given problem, we have:

AB = [[-4 * 3 + -6 * 2, -4 * -4 + -6 * -1], [4 * 3 + 3 * 2, 4 * -4 + 3 * -1]]

Simplifying the expression further:

AB = [[-12 - 12, 16 + 6], [12 + 6, -16 - 3]]

AB = [[-24, 22], [18, -19]]