457,794 views
16 votes
16 votes
Would greatly appreciate the help!

Considering the two reactants,
9.0 mol Na2S can form 9.0 mol CuS and
8.0 mol CuSO4 can form 8.0 mol CuS.
The molar mass of CuS is 95.62 g/-
mol. What mass, in grams, of CuS
actually forms during the reaction?
?]g CuS
Round your answer to the tens place.

Would greatly appreciate the help! Considering the two reactants, 9.0 mol Na2S can-example-1
User Burmese Bug
by
3.0k points

2 Answers

18 votes
18 votes

Answer:

765.0 grams

Step-by-step explanation:

User Rihekopo
by
2.6k points
22 votes
22 votes

Answer:

The total number of moles of CuS that can be formed from the given reactants is the sum of the number of moles of CuS that can be formed from each reactant, which is 9.0 mol + 8.0 mol = 17.0 mol. To find the mass of CuS that can be formed, we need to multiply the number of moles by the molar mass of CuS. The molar mass of CuS is 95.62 g/mol, so the total mass of CuS that can be formed is 17.0 mol * 95.62 g/mol = 1618.34 g. Rounded to the tens place, this is 1600 g.

Step-by-step explanation:

User Muhammad Razib
by
3.2k points