195k views
4 votes
If a circuit has a capacitor of 50 F and a source voltage of 120 VDC through a resistance of 50 k, how long will it take to fully charge?

User Moertel
by
8.2k points

1 Answer

6 votes

Final answer:

The time to fully charge a capacitor in an RC circuit is typically considered to be around 5 times the RC time constant (τ).

With a capacitance of 50 F and a resistance of 50 kΩ, it would take approximately 12,500,000 seconds or around 144.65 days to fully charge the capacitor.

Step-by-step explanation:

To determine how long it will take for the capacitor to fully charge, we can use the concept of the RC time constant (τ), which is the time it takes for a capacitor to charge to about 63.2% of its maximum voltage.

The RC time constant is calculated by multiplying the resistance (R) by the capacitance (C), where R is in ohms (Ω) and C is in farads (F).

In this case, with a capacitance of 50 F and a resistance of 50 kΩ, the time constant τ is:

τ = R × C

= (50,000 Ω) × (50 F)

= 2,500,000 seconds

However, charging to the full capacity is generally considered to be around 5 times the RC time constant, which accounts for over 99% of the total charge.

Therefore, the time to fully charge the capacitor is approximately:

5 × τ = 5 × 2,500,000 s

= 12,500,000 s

In practical terms, charging a capacitor with such a large capacitance and resistance would be an unusual case, and it would take a significantly long time (approximately 144.65 days)

User Moe Sisko
by
9.4k points