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How to solve the following

9^2x+1 = 27^x-3

User MadLax
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1 Answer

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Answer:

To solve this equation, we can first rewrite it in a form that is easier to work with. We can do this by dividing both sides by 9^2, which gives us:

(9^2x+1)/9^2 = 27^x-3

We can then simplify the left side of the equation by taking the square root of both sides, which gives us:

3x+1/3 = 3^x-3

We can then rearrange the terms on the left side of the equation to get:

3x = 3^x-6

We can then subtract 3^x from both sides of the equation, which gives us:

3x-3^x = -6

We can then divide both sides of the equation by 3-3^x, which gives us the final solution:

x = -6 / (3-3^x)

This is the value of x that satisfies the original equation.

Explanation:

User Aaron Meier
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