Final answer:
To find the equation of line q, which is parallel to line p and includes the point (2, -1), we can use the point-slope form of a linear equation. The equation of line q is y = 17x - 35.
Step-by-step explanation:
To find the equation of line q, which is parallel to line p and passes through the point (2, -1), we can use the fact that parallel lines have the same slope. To find the equation of line q, which is parallel to line p and includes the point (2, -1), we can use the point-slope form of a linear equation.
The equation of line q is y = 17x - 35. The equation of line p is y = 17x - 10, so the slope of line p is 17. Since line q is parallel to line p, it will also have a slope of 17.
Using the point-slope form of a linear equation, y - y1 = m(x - x1), where (x1, y1) is a point on the line and m is the slope, we can substitute the given point (2, -1) and the slope 17 into the equation to find the equation of line q.
Therefore, the equation of line q is y - (-1) = 17(x - 2), which simplifies to y = 17x - 35.