Answer:
To find three integer or decimal solutions to the equation 5x + 4y = 20, we can first divide both sides of the equation by the GCF of the coefficients, which is 1. This gives us the equation 5x + 4y = 20/1, which can be rewritten as 5x + 4y = 20. We can then use the substitution method to solve for x in terms of y, by setting 4y = 20 - 5x and solving for x. This gives us x = (20 - 4y) / 5. Substituting this expression for x into the original equation, we get 5((20 - 4y) / 5) + 4y = 20, which simplifies to 20 - 4y + 4y = 20, or 20 = 20. This means that any value of y that satisfies the equation will also satisfy the original equation.
For example, if we choose y = 3, then x = (20 - 4 * 3) / 5 = 2, and the solution (x, y) = (2, 3) satisfies the equation 5x + 4y = 20. Similarly, if we choose y = 0, then x = (20 - 4 * 0) / 5 = 4, and the solution (x, y) = (4, 0) satisfies the equation. Finally, if we choose y = -1, then x = (20 - 4 * -1) / 5 = 5, and the solution (x, y) = (5, -1) satisfies the equation.
The solution set for the equation 5x + 4y = 20 is the set of all ordered pairs (x, y) that satisfy the equation. The three solutions we found are (2, 3), (4, 0), and (5, -1), and these solutions can be plotted on a coordinate grid to show the solution set. The graph of the solution set is a line that passes through the points (2, 3), (4, 0), and (5, -1).
Explanation: