Question

a 95 N force exerted at the end of 50 cm long torque wrench gives rise to a torque of 10 N/m. What is the angle (assumed to be less than 90 degrees) between the wrench handle and the direction of the applied force.

Answer 1

Γ = r X F = r F sin θ

sin θ = 10 / .50 * 95 rearrange torque equation

sin θ = 10 / 47.5 = .210

θ = 12 deg angle between force and handle