Question

As John leaves the diving board in a layout position, he has an angular velocity of 3 and a moment of inertia of 11.1 kg.m2 about a sagittal plane (somersault) axis. He tucks to do a back flip, reducing his moment of inertia to 3.6 kg.m2. What is his angular velocity in the tuck position?

Answer 1

9.25 rad/ second

Step-by-step explanation:

i am assuming by 3 you meant rad/ second for angular velocity.

velocity initial x inertia initial = velocity final x inertia final

3x11.1= velocity final (3.6)