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Given the equation 8x + y = 16, find the values of x and y for the points (6, -32) and (2, 0).

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Final answer:

Both points (6, -32) and (2, 0) satisfy the equation 8x + y = 16, which is confirmed by substituting the x and y values into the equation and verifying that both sides are equal.

Step-by-step explanation:

The question asks to verify if the points (6, -32) and (2, 0) satisfy the equation 8x + y = 16. To do this, we will substitute the x and y values of each point into the equation and see if the equation holds true.

For the point (6, -32), we substitute x = 6 and y = -32 into the equation:

8(6) + (-32) = 48 - 32 = 16

Since the left side equals to 16, which is the right side of the equation, the point (6, -32) satisfies the equation.

For the point (2, 0), we substitute x = 2 and y = 0 into the equation:

8(2) + 0 = 16 + 0 = 16

Similarly, the left side equals to 16, so the point (2, 0) also satisfies the equation.

To find the values of x and y for the points (6, -32) and (2, 0) in the equation 8x + y = 16, we can substitute the x and y values into the equation and solve for the unknowns.

For the point (6, -32), we have 8(6) + (-32) = 16, which simplifies to 48 - 32 = 16. This is true, so (6, -32) satisfies the equation.

For the point (2, 0), we have 8(2) + (0) = 16, which simplifies to 16 = 16. This is also true, so (2, 0) satisfies the equation.

Therefore, the values of x and y for the points (6, -32) and (2, 0) in the equation 8x + y = 16 are x = 6 and y = -32, and x = 2 and y = 0, respectively.

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