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21 votes
21 votes
The length of a rectangular parking lot is 16 yards greater than 3 times its width, x, in yards. Enter the function f(x) that describes the area, in square yards, as a function of the width, x.

f(x) = _____

User Atul Chavan
by
2.9k points

2 Answers

19 votes
19 votes

f(x) = Area = (length)(width)

width = x

The length is 16 yards greater than 3 times x

length = 3x+16

f(x) = (3x+16)(x) = 3x^2 + 16x

User Francesquini
by
3.2k points
14 votes
14 votes

Answer:

  • f(x) = 3x² + 16x

Explanation:

We have been given that -- The length of a rectangular parking lot is 16 yards greater than 3 times its width, x, in yards

Length of parking lot is 16 + 3x

Width of parking lot is x

We have to write the function f(x) that describes the area, in square yards, as a function of the width, x

Area of rectangle is Length × width


\sf Area = f(x)

put value of length and width here,


\sf f(x) = (16 + 3x)(x )


\sf f(x) = 3x^2 + 16x

Therefore, f(x) = 3x² + 16x

User Adonis L
by
2.5k points
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