99.9k views
1 vote
Yoko pumped 20 gallons of water out of her pool. This was done over a period of 10 minutes at a constant rate. What was the change in the amount of water in the pool each minute?

User Mawcs
by
8.4k points

1 Answer

4 votes

Final answer:

Yoko pumped out water at a constant rate of 2 gallons per minute, calculated by dividing the total amount of water removed (20 gallons) by the total time taken (10 minutes).

Step-by-step explanation:

The question at hand requires us to find the rate of change of the water level in Yoko's pool. Yoko has pumped out 20 gallons of water from her pool over a period of 10 minutes at a constant rate. To find the change in the amount of water in the pool each minute, we would perform a simple division calculation.

To find the change in the pool each minute, we divide the total amount of water pumped out by the total time. So the calculation would be:

  1. 20 gallons ÷ 10 minutes = 2 gallons per minute.

So, the rate of change in the amount of water in Yoko's pool is 2 gallons per minute.

User Coufu
by
8.0k points