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What is the value of x in the equation 4 x plus 8 y equals 40, when y equals 0.8?Which shows the correct solution of the equation, when ?

User Fossil
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1 Answer

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Explanation:

To find the value of x in the equation 4x + 8y = 40, when y = 0.8, we can substitute the value of y into the equation and solve for x.

Substituting y = 0.8 into the equation, we have:

4x + 8(0.8) = 40

Simplifying the equation, we get:

4x + 6.4 = 40

To isolate x, we need to move 6.4 to the other side of the equation by subtracting it from both sides:

4x = 40 - 6.4

4x = 33.6

Finally, we can solve for x by dividing both sides of the equation by 4:

x = 33.6 / 4

x = 8.4

Therefore, the value of x in the equation 4x + 8y = 40, when y = 0.8, is x = 8.4.

Now, let's move on to the solution of the equation. The equation 4x + 8y = 40 represents a linear relationship between x and y. We can interpret this equation as follows: for every increase of 1 in x, the value of y increases by 2. In other words, the coefficient of x (4) represents the rate of change of y with respect to x.

To find the solution of the equation, we can plot the equation on a graph and find the point where the line intersects the y-axis. This point represents the value of y when x is equal to 0. In this case, when x = 0, the equation becomes:

4(0) + 8y = 40

8y = 40

Dividing both sides by 8, we get:

y = 5

Therefore, the solution of the equation is (0, 5), which means that when x = 0, y = 5.

User Bryan Guillen
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