Final answer:
The magnitude and direction of torque on the current-carrying loop are calculated using the formula for torque in a magnetic field, and the system potentially serves as a simple electric motor.
Step-by-step explanation:
The question relates to Physics, specifically to magnetism and the calculation of torque on a current-carrying loop in a magnetic field, which is a topic typically covered in high school physics classes. To find the magnitude of the torque on the loop (τ), we can use the formula τ = nIABsin(θ), where n is the number of turns (200 turns), I is the current (100 A), A is the area of the loop (πr^2, with r = 0.5 m), B is the magnetic field strength (3.00 x 10^-5 T), and θ is the angle between the normal to the plane of the loop and the magnetic field (90° since the field is parallel to the ground and the loop is vertical).
The direction of the torque can be determined using the right-hand rule, which gives us a torque vector pointing in the east-west direction, along the axis of the loop. Regarding its practicality as a motor, if the system allows the loop to rotate without other external influences, it could potentially serve as a simple electric motor.