Question

A television screen measures 32 inches diagonally, and its aspect ratio is 4 : 3. Find the width and height of the screen. (Round your answers to one decimal place.)

Answer 1

To find the width and height of the television screen with a diagonal measurement of 32 inches and an aspect ratio of 4:3, use the concept of similar triangles and set up a proportion.

Step-by-step explanation:

To find the width and height of the television screen, we can use the concept of similar triangles. Since the aspect ratio is given as 4:3, we can assume that the width of the screen is 4x and the height is 3x, where x is a constant. We can set up a proportion using the given diagonal measurement:

32 / x = √(4^2 + 3^2) / (4x) = 5 / 4x

Solving for x, we find that x = 32 / 5 = 6.4. Therefore, the width of the screen is 4 * 6.4 = 25.6 inches, and the height is 3 * 6.4 = 19.2 inches.