Final answer:
The car travels a distance of 360 ft in 6.00 s and reaches a final velocity of 250.0 ft/s.
Step-by-step explanation:
In this problem, the knowns are the initial velocity, final velocity, and time. The unknown in part (c) is the distance traveled by the car, while in part (d) it is the final velocity. To solve for the distance traveled, we can use the equation:
distance = average velocity × time
In this case, the average velocity is the sum of the initial and final velocities divided by 2. Plugging in the given values, we have:
average velocity = (10.0 ft/s + 50.0 ft/s) ÷ 2 = 60.0 ft/s
distance = 60.0 ft/s × 6.00 s = 360 ft
To solve for the final velocity, we can use the equation:
final velocity = initial velocity + (acceleration × time)
In this case, the initial velocity is 10.0 ft/s, the acceleration is (final velocity - initial velocity) ÷ time, and the time is 6.00 s. Plugging in the given values, we have:
acceleration = (50.0 ft/s - 10.0 ft/s) ÷ 6.00 s = 40.0 ft/s²
final velocity = 10.0 ft/s + (40.0 ft/s² × 6.00 s) = 250.0 ft/s