Final answer:
To find the mass in pounds of 825.3 cm³ of a liquid with a specific gravity of 0.85, multiply the volume by the density (0.85 g/cm³) to get the mass in grams, and then convert grams to pounds, resulting in approximately 1.546 pounds.
Step-by-step explanation:
To calculate the mass in pounds of 825.3 cm³ of a liquid with a specific gravity of 0.85, we can use the properties of specific gravity. First, we determine the density of water, which is approximately 1.00 g/cm³ (or 1 g/mL), and since specific gravity is the ratio of the density of the substance to the density of water, we can say that the density of the liquid is 0.85 g/cm³.
Next, we calculate the mass of the liquid using its density:
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- Mass (in grams) = Density (g/cm³) × Volume (cm³)
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- Mass (in grams) = 0.85 g/cm³ × 825.3 cm³
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- Mass (in grams) = 701.505 g
To convert this mass from grams to pounds, we use the conversion factor that 1 pound is equal to approximately 453.59237 grams:
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- Mass (in pounds) = Mass (in grams) / 453.59237 g/pound
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- Mass (in pounds) = 701.505 g / 453.59237 g/pound
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- Mass (in pounds) ≈ 1.546 pounds
Therefore, the mass of 825.3 cm³ of the liquid substance with a specific gravity of 0.85 is approximately 1.546 pounds.