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A car moving at 11 m/s is uniformly accelerated at the rate of 0.2 m/s^2. What is the speed of the car 20.06 s after the acceleration begins?

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Final answer:

After 20.06 seconds of accelerating at a rate of 0.2 m/s² from an initial velocity of 11 m/s, the car's speed will be 15.012 m/s.

Step-by-step explanation:

To find the speed of the car 20.06 seconds after the acceleration begins, we can use the equation for uniform acceleration:

v = u + at

Where v is the final velocity, u is the initial velocity, a is the acceleration, and t is the time. Given that the initial velocity (u) is 11 m/s, the acceleration (a) is 0.2 m/s², and the time (t) is 20.06 seconds, we can substitute these values into the equation:

v = 11 + (0.2)(20.06)

v = 11 + 4.012

v ≈ 15.012 m/s

Therefore, the speed of the car 20.06 seconds after the acceleration begins is approximately 15.012 m/s.

v = 11 m/s + (0.2 m/s² × 20.06 s) = 11 m/s + 4.012 m/s = 15.012 m/s

Therefore, the speed of the car 20.06 seconds after the acceleration begins is 15.012 m/s.

User Jithin Shaji
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