Final answer:
After 20.06 seconds of accelerating at a rate of 0.2 m/s² from an initial velocity of 11 m/s, the car's speed will be 15.012 m/s.
Step-by-step explanation:
To find the speed of the car 20.06 seconds after the acceleration begins, we can use the equation for uniform acceleration:
v = u + at
Where v is the final velocity, u is the initial velocity, a is the acceleration, and t is the time. Given that the initial velocity (u) is 11 m/s, the acceleration (a) is 0.2 m/s², and the time (t) is 20.06 seconds, we can substitute these values into the equation:
v = 11 + (0.2)(20.06)
v = 11 + 4.012
v ≈ 15.012 m/s
Therefore, the speed of the car 20.06 seconds after the acceleration begins is approximately 15.012 m/s.
v = 11 m/s + (0.2 m/s² × 20.06 s) = 11 m/s + 4.012 m/s = 15.012 m/s
Therefore, the speed of the car 20.06 seconds after the acceleration begins is 15.012 m/s.