Question

A set of 4 consecutive integers has a sum of 210. What is the greatest of the 4 integers?

Answer 1

Step-by-step explanation:

4 consecutive integers.

x = the first (and smallest) integer.

the other 3 integers are

x + 1

x + 2

x + 3

x + (x + 1) + (x + 2) + (x + 3) = 210

x + x + 1 + x + 2 + x + 3 = 210

4x + 6 = 210

4x = 204

x = 51

the greatest of the 4 integers is then

x + 3 = 51 + 3 = 54

Answer 2

To find the greatest of the 4 consecutive integers, set up an equation and solve for x. The greatest integer is 54.

Step-by-step explanation:

To find the greatest of the 4 consecutive integers, we need to determine the middle two numbers. Let's assume the first number is x. The four consecutive integers would be x, x+1, x+2, and x+3. We know that the sum of these integers is 210, so we can set up an equation:

x + (x+1) + (x+2) + (x+3) = 210

Combining like terms, we get:
4x + 6 = 210

Subtracting 6 from both sides gives:
4x = 204

Dividing by 4, we find:
x = 51

Therefore, the four consecutive integers are 51, 52, 53, and 54. The greatest of these integers is 54.