Question

You wish to dilute some chemical with a diluting agent. You have 50mL of chemical, and the ratio must be 1:60 (chemical: agent). The diluting agent is kept in three sizes 1 Liter, 5 Liters, and 10 Liters. You have to carry it to the mixing station, which is 300 meters away, so you want to carry the smallest size that will do the job. Which container would you take?

Answer 1

To dilute 50 mL of a chemical in a 1:60 ratio, the total diluted volume needed is 3,000 mL or 3 L. The smallest available container that can accommodate this volume is the 5 Liters container.

Step-by-step explanation:

The student needs to dilute a chemical substance with a diluting agent in a ratio of 1:60, given that they have 50 mL of the chemical. To figure out the size of the diluting agent container required to achieve this ratio, we use the following steps:

1. First, we need to determine the total volume of the solution after the chemical has been diluted. This can be calculated by multiplying the volume of the chemical by the dilution ratio: 50 mL × 60 = 3,000 mL.
2. Next, convert this total volume from milliliters to liters, as the diluting agent is measured in liters. Since there are 1,000 milliliters in a liter, 3,000 mL is equivalent to 3 liters.
3. Now, we select the smallest container size that can accommodate the 3 liters needed for the dilution. The options are 1 Liter, 5 Liters, and 10 Liters containers. Therefore, the 5 Liters container is the suitable size.

The 5 Liters container is the minimum size that can hold the chemical and the diluting agent for the required dilution.