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In Class Horizontal problem: A5 kg sled is dragged, at a constant speed,

across a rough horizontal surface with 28 N of force. What is the
coefficient of friction between the surface and the sled?

1 Answer

7 votes

Final answer:

The coefficient of friction between the surface and the sled is approximately 0.5714.

Step-by-step explanation:

To find the coefficient of friction between the surface and the sled, we need to use the formula for frictional force, which is given by:

Ff = μN

where Ff is the frictional force, μ is the coefficient of friction, and N is the normal force. In this case, the normal force is equal to the weight of the sled, which is given by:

N = mg

where m is the mass of the sled and g is the acceleration due to gravity. Therefore, the frictional force can be expressed as:

Ff = μmg

Given that the force applied to the sled is 28 N, which is equivalent to the frictional force, we can rearrange the formula to solve for the coefficient of friction:

μ = Ff / (mg)

Substituting the given values, we have:

μ = 28 N / (5 kg * 9.8 m/s2)

μ = 0.5714

Therefore, the coefficient of friction between the surface and the sled is approximately 0.5714.

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