Answer:
The pH of the buffer is 4.77
Step-by-step explanation:
Using Henderson-Hasselbalch equation we can solve the pH of the buffer:
pH = pKa + log [A⁻] / [HA]
Where pH is the pH of the buffer
pKa is -log Ka = 5.056
[A⁻] = [NaA] = 0.2M
[HA] = 0.39M
Replacing:
pH = 5.056+ log [0.2] / [0.39]
pH = 4.77
The pH of the buffer is 4.77