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A car accelerates from 6 m/s to 20 m/s. this takes place over 50.00m what is its rate of acceleration?

options:
4.63 m/s^2
4.36m/s^2
4.06m/s^2
3.64 m/s^2

1 Answer

5 votes

Final answer:

The rate of acceleration for the car that speeds up from 6 m/s to 20 m/s over a distance of 50 m is calculated using the formula a = (v² - u²) / (2s), which results in an acceleration of 3.64 m/s². The correct answer is option: 3.64 m/s²

Step-by-step explanation:

To determine the rate of acceleration of a car that changes its speed from 6 m/s to 20 m/s over a distance of 50.00 m, we can use the kinematic equations of motion. One such equation is:

v² = u² + 2as

Where:
v = final velocity (20 m/s)
u = initial velocity (6 m/s)
a = acceleration
s = distance traveled (50 m)

Rearranging the formula to solve for acceleration a, we get:

a = (v² - u²) / (2s)

Substituting the given values:

a = (20² - 6²) / (2 × 50)

a = (400 - 36) / 100

a = 364 / 100

a = 3.64 m/s²

Therefore, the rate of acceleration is 3.64 m/s².

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