Final answer:
The amount of heat required to raise the temperature of a 65g sample of water from 32°C to 65°C is calculated using the specific heat capacity of water and the formula Q = m × c × ΔT, resulting in 8994.36 Joules.
Step-by-step explanation:
To calculate the amount of heat required to raise the temperature of a 65g sample of water from 32°C to 65°C, we use the formula:
Q = m × c × ΔT
Where:
Q = amount of heat (in Joules),
m = mass of the substance (in grams),
c = specific heat capacity (J/g°C),
ΔT = change in temperature (°C).
The specific heat capacity (c) of water is 4.184 J/g°C. The mass (m) of water is given as 65g, and the change in temperature (ΔT) is 65°C - 32°C = 33°C.
Plugging the values into the equation gives us:
Q = 65g × 4.184 J/g°C × 33°C = 8994.36 J
Therefore, the amount of heat required is 8994.36 Joules.