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A money bag contains equal numbers of quarters, dimes, and nickels, totaling $36.80. How many of each coin are in the bag? ​

User Sigfried
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1 Answer

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Final answer:

The money bag contains 92 quarters, 92 dimes, and 92 nickels, each contributing equally to the total of $36.80.

Step-by-step explanation:

To solve the problem of determining how many quarters, dimes, and nickels are in a money bag totaling $36.80, we first need to express the value of each coin type in terms of dollars:

  • A quarter is worth $0.25.
  • A dime is worth $0.10.
  • A nickel is worth $0.05.

If we let the number of each coin type be x, we can set up an equation for the total value:

0.25x + 0.10x + 0.05x = 36.80

Combining like terms gives us:

0.40x = 36.80

Dividing both sides of the equation by 0.40 gives us the number of each coin type:

x = 36.80 / 0.40

x = 92

So, there are 92 quarters, 92 dimes, and 92 nickels in the money bag.

User Maura
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