Question

A runner moves 2.88 m/s north. She accelerates at 0.350 m/s^2 at a -52 degree angle. At the point in the motion where she is running directly east, what is triangle x?

Answer 1

The question seems to be a physics problem about a runner's velocity and acceleration vectors, but it lacks clear context or a diagram to provide an accurate answer for 'triangle x'.

Step-by-step explanation:

The question involves a runner moving north at a certain velocity and then accelerating in a different direction. You've asked about 'triangle x,' which may refer to a diagram not provided. Typically, in physics problems, we analyze the components of velocity and acceleration to determine the resultant motion. However, with the details given, we cannot provide a precise answer without additional context or a specific diagram referred to as 'triangle x.'

As the runner is initially moving north and then accelerates at a -52 degree angle, we would need to use vector addition to calculate the resultant velocity at the point where she is running directly east. The acceleration would have a north/south and east/west component that would change her velocity in the northward direction until she is moving east. The 'triangle x' could be a part of a vector diagram showing these components.