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A volleyball player hits the ball when it is h feet above the ground. The volleyball net is 8 feet tall. The ball lands 15 feet away from the base of the net, as shown.What is the height of the ball when the player hits it? Round to the nearest tenth of a foot.

User SQRCAT
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Final answer:

The gravitational potential energy of the ball just before the netball player shoots it is 10.78 joules, calculated using the formula GPE = mgh with a ball mass of 0.5 kg and height of 2.2 m above the ground.

Step-by-step explanation:

The question concerns the gravitational potential energy of a netball when a player is about to shoot it into the goal net. To find the gravitational potential energy (GPE), the formula GPE = mgh is used, where m is the mass of the ball, g is the acceleration due to gravity (approximately 9.8 m/s2 on Earth), and h is the height of the ball above the reference point, in this case, the ground.

Given that the netball player is 1.7 m tall and the ball is held 0.5 m above her head, the total height h of the ball is 2.2 m (1.7 m + 0.5 m). With a ball mass m of 0.5 kg, the gravitational potential energy just before the shot is GPE = 0.5 kg * 9.8 m/s2 * 2.2 m = 10.78 J (joules).

User Meghdad Hadidi
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