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what is the volume of a cone with a radius of 2 ft and a height of 9 ft use 3.14 for pie show your work

User Lanesha
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1 Answer

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Final answer:

The volume of a cone with a radius of 2 ft and a height of 9 ft, using 3.14 for pi, is 37.68 cubic feet.

Step-by-step explanation:

Calculating the Volume of a Cone

To calculate the volume of a cone, we use the formula:

\(V = \frac{1}{3} \pi r^2 h\)

In this case, the radius (r) is 2 ft and the height (h) is 9 ft. We are also given that we should use 3.14 for \(\pi\). Substituting these values into the formula, we get:

\(V = \frac{1}{3} \times 3.14 \times (2 ft)^2 \times 9 ft\)

First, calculate the area of the base (circle) which is \(\pi r^2\).

\(Area = 3.14 \times (2 ft)^2

= 3.14 \times 4 ft^2

= 12.56 ft^2\)

Then, multiply the area by the height and divide by 3:

\(V = \frac{1}{3} \times 12.56 ft^2 \times 9 ft

= \frac{113.04 ft^3}{3}

= 37.68 ft^3\)

Thus, the volume of the cone is 37.68 cubic feet.

User Badr Bellaj
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