Question

An airplane starts from rest and accelerates at a constant 3.00m/s^2 for 20.0 seconds. What is its displacement in this time?

Answer 1

To calculate the displacement of an airplane accelerated from rest at 3.00 m/s^2 for 20.0 seconds, the kinematic equation s = ut + ½at^2 is used, resulting in a displacement of 600 meters.

Step-by-step explanation:

The question pertains to constant acceleration in Physics, specifically how to calculate displacement when an airplane accelerates from rest. To find the displacement of an airplane accelerating from rest at 3.00 m/s2 for 20.0 seconds, we use the kinematic equation for constant acceleration:

• s = ut + ½at2

Where:

• s = displacement
• u = initial velocity (0 m/s, since the airplane starts from rest)
• a = acceleration (3.00 m/s2)
• t = time (20.0 seconds)

Plugging the values into the equation:

s = (0 m/s)(20.0 s) + ½(3.00 m/s2)(20.0 s)2

s = 0 + ½(3.00 m/s2)(400.0 s2)

s = 0 + 600.0 m

So, the displacement of the airplane is 600 meters.