Question

Lisa wants to buy two different games to play this weekend. She has a choice of two stores from which to buy the games. At the first store one of the games is $10 cheaper than the other game. The second store normally sells each game for $2 more than the first store, but has an offer at the moment that the more expensive game is half price when the two games are bought together. Lisa can save $6 in total by shopping at the second store rather than the first. What is the total that Lisa will pay for the games?

Answer 1

To find the total that Lisa will pay for the games, let's represent the prices of the games at the first store as x and x-10 (since one game is $10 cheaper than the other).

Step-by-step explanation:

To find the total that Lisa will pay for the games, let's represent the prices of the games at the first store as x and x-10 (since one game is $10 cheaper than the other). The second store sells each game for $2 more than the first store, so the prices of the games at the second store will be x+2 and x-10+2 = x-8.

Since the more expensive game is half price when both games are bought together, if Lisa buys the games at the second store, the total price will be (x+2) + (x-8)/2 = 2x-6. If Lisa buys the games at the first store, the total price will be x + (x-10) = 2x-10. We know that Lisa can save $6 by shopping at the second store, so we can set up the equation 2x-10 - (2x-6) = 6. Solving this equation, we find that x = 12.

Substituting x = 12 into the expression 2x-6, we find that the total price that Lisa will pay for the games is $18.