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If point Q is between P and R, and PO=25 and OR=-x+8 and PR--19x-111, then the value of x is ______

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Final answer:

The value of x is determined to be 7.2 by setting up the equation 25 - x + 8 = 19x - 111 based on the distances between points P, Q, and R and solving for x.

Step-by-step explanation:

The question asks to find the value of x when given that point Q is between points P and R, with distances PO=25, OR=-x+8, and PR=19x-111. To solve for x, we consider that the sum of PO and OR should be equal to PR since Q is between P and R on a line segment. Therefore, the equation is PO + OR = PR. Substituting the given values, we have 25 + (-x + 8) = 19x - 111.

By simplifying and solving the equation, you get:

25 - x + 8 = 19x - 111

33 - x = 19x - 111

Adding x to both sides and adding 111 to both sides gives:

33 + 111 = 19x + x

144 = 20x

Dividing both sides by 20 gives:

x = 144 / 20

x = 7.2

Therefore, the value of x is 7.2.

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