Question

2N2​O2​→4NO2​+O2​. How many moles of N2​O2​ are needed to produce 7.90 moles of NO2​?

A) 3.95 moles
B) 7.90 moles
C) 15.80 moles
D) 1.975 moles

Answer 1

To produce 7.90 moles of NO₂, 3.95 moles of N₂O₅ are required according to the stoichiometric ratio from the balanced chemical equation, making the answer (A) 3.95 moles.

Step-by-step explanation:

To determine how many moles of N₂O₅ are needed to produce 7.90 moles of NO₂, we use the stoichiometry of the balanced chemical reaction. According to the equation, 2 N₂O₅ → 4 NO₂ + O₂, 2 moles of N₂O₅ produce 4 moles of NO₂. To find the moles of N₂O₅ needed, we set up a proportion based on this molar ratio:

• (2 mol N₂O₅) / (4 mol NO₂) = (x mol N₂O₅) / (7.90 mol NO₂)

Solving for x gives us:

x = (7.90 mol NO₂) × (2 mol N₂O₅) / (4 mol NO₂) = 3.95 moles of N₂O₅

Therefore, the answer is (A) 3.95 moles of N₂O₅ are needed to produce 7.90 moles of NO₂.