Question

To rent a certain meeting room, a college charges a reservation fee of $18 and an additional fee of $4 per hour. The chemistry club wants to spend at most $38 on renting the room. What are the possible numbers of hours the chemistry club could rent the meeting room?

Answer 1

The Chemistry Club could rent the meeting room for up to 5 hours, given the reservation fee and hourly cost with a budget of $38.

Step-by-step explanation:

The correct answer is option: To determine the possible numbers of hours the chemistry club could rent the meeting room, we need to set up an inequality based on the costs presented.

The reservation fee is $18 and the cost per hour is $4. The chemistry club wants to spend at most $38. We can create the following inequality to find the number of hours (h):

18 + 4h ≤ 38

First, subtract the reservation fee from both sides of the inequality:

4h ≤ 38 - 18

4h ≤ 20

Now divide both sides by 4 to solve for h:

h ≤ 20 / 4

h ≤ 5

Therefore, the chemistry club could rent the meeting room for up to 5 hours.

To find the possible numbers of hours the chemistry club could rent the meeting room, we need to set up an inequality based on the given information. Let's assume the number of hours the chemistry club can rent the room is x. The reservation fee is $18 and the additional fee per hour is $4. So, the total cost of renting the room is $18 + $4x.

The chemistry club wants to spend at most $38 on renting the room, which means the total cost should be less than or equal to $38. So, we can write the inequality: $18 + $4x ≤ $38. Now, we can solve this inequality to find the possible values of x.