Final answer:
The equation of a line that passes through (7/2, 10/11) and is perpendicular to the y-axis, which is a horizontal line, is simply y = 10/11.
Step-by-step explanation:
To write the equation of a line that passes through the point (7/2, 10/11) and is perpendicular to the y-axis, we must understand that a line perpendicular to the y-axis is a horizontal line. Since it's horizontal, its slope, or 'm' in the equation y = mx + b, is 0. Therefore, the equation of any horizontal line will not have an 'x' term because the slope is 0; it will only have a 'y' intercept, which is the 'b' in our equation.
The line's y-value remains constant no matter what the x-value is. Since our line passes through the point (7/2, 10/11), the y-value of 10/11 will be the y-intercept (b).
Thus, the equation of a line perpendicular to the y-axis passing through the point (7/2, 10/11) is y = 10/11.