136k views
0 votes
Two bumper cars move in a straight line with the following equations of motion:

X1 = -4.0 m + (1.9 m/s)t
X2 = 8.8 m + (-2.1 m/s)t
What time do they collide?
a) When t = 2 s
b) When t = 4 s
c) When t = 6 s
d) When t = 8 s

User Brienne
by
7.7k points

1 Answer

5 votes

Final answer:

The two bumper cars collide at t = 1.2s.

Step-by-step explanation:

In order to find the time at which the two bumper cars collide, we need to find the time at which their positions are equal. To do that, we can set the two position equations equal to each other and solve for t:

X1 = X2 -4.0 + 1.9t = 8.8 - 2.1t 4.0 + 2.1t = 8.8 - 1.9t 4.0t = 4.8 t = 1.2

The bumper cars collide at t = 1.2 s, so none of the given answer choices are correct.

User Skin
by
8.1k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories