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Prove the following:

a) sin (90°+a). cos (180°-a) - sin (180° - a).cos (90°)
b) cot (180° + θ). tan (270°-θ) = cot (θ)

1 Answer

5 votes

Final answer:

The student sought to prove given trigonometric identities, but due to potential typographical errors, a complete demonstration cannot be provided without the correct expressions.

Step-by-step explanation:

The question asks to prove that sin (90°+a) cos (180°-a) - sin (180° - a) cos (90°) and cot (180° + θ) tan (270°-θ) = cot (θ). To solve these trigonometric identities, we can apply known formulas such as the sine addition formula, the cosine addition formula, and the properties of trigonometric functions related to their periodicity and symmetry. However, the question appears to have typographical errors and may be incomplete, making it impossible to provide a complete demonstration without the correct expressions. Therefore, I cannot confidently provide a correct answer to this question in its current form.

To prove:

a) sin (90°+a).cos (180°-a) - sin (180° - a).cos (90°) = 0

b) cot (180° + θ).tan (270°-θ) = cot (θ)

a) Using the trigonometric identities sin (90°+a) = cos a and cos (180°-a) = -cos a, we can substitute these values into the expression and simplify to get 0.

b) Using the trigonometric identities cot (180° + θ) = -cot θ and tan (270°-θ) = -cot θ, we can substitute these values into the expression and simplify to get cot θ.

User RoberRM
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