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Write a quadratic equation (y = ax^2 + bx + c) with x-intercepts at (3, 0) and (-1, 0).

User Simhor
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Final answer:

To write a quadratic equation with x-intercepts at (3, 0) and (-1, 0), we can use the fact that the x-intercepts occur when y = 0. Therefore, we can substitute these values into the quadratic equation and solve for the coefficients.

Step-by-step explanation:

To write a quadratic equation with x-intercepts at (3, 0) and (-1, 0), we can use the fact that the x-intercepts occur when y = 0. Therefore, we can substitute these values into the quadratic equation and solve for the coefficients:

When x = 3, y = 0: 0 = a(3)^2 + b(3) + c

When x = -1, y = 0: 0 = a(-1)^2 + b(-1) + c

Using these equations, we can solve for a, b, and c. In this case, the quadratic equation with x-intercepts at (3, 0) and (-1, 0) is y = x^2 - x - 6.

User Dave Batton
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