Question

For sailboats to travel into the wind, it is sometimes necessary to tack, or move in a zigzag pattern. A sailboat in Canim Lake travels 6 km due north and then 6 km due west. From there, the boat travels 5 km due north and then 5 km due west. How far is the boat from its starting point? The distance can be expressed as : csqrt(d)km. The value for cis: Ay and the value for d is: a

Answer 1

The sailboat is √122 km from its starting point after traveling in a zigzag pattern first 6 km northward and then 6 km westward, followed by 5 km northward and 5 km westward.

Step-by-step explanation:

The question involves calculating the distance a sailboat is from its starting point after moving in a zigzag pattern. This involves using Pythagorean theorem to find the result, as the boat's movement creates a right-angled triangle.

First, the sailboat travels 6 km due north and then 6 km due west, making a right-angled triangle. To find the distance from the starting point at this stage, we calculate the hypotenuse (c) of the triangle with sides of 6 km each:

c = √(6^2 + 6^2) = √(36 + 36) = √72

Next, the boat travels another 5 km due north and then 5 km due west, forming another right-angled triangle. We find the hypotenuse of this second triangle in the same way:

c = √(5^2 + 5^2) = √(25 + 25) = √50

To find the total distance from the starting point, we add the two hypotenuses:

Total distance = √72 + √50 = √(72 + 50) = √122

So, the boat is √122 km from its starting point.