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Given the line segment AB=28 cm and a point C on directed line segment AB that partitions AB into the ratio 3 to 1, find the lengths of line segments AC and CB.

a)AC=21 cm CB=7 cm
b)AC=22 cm CB=6 cm
c)AC=14 cm CB=14 cm
d)AC=7 cm CB=21 cm

User Medo
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1 Answer

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Final answer:

The segment AB is divided into 3 to 1 ratio by point C to find the lengths of AC and CB. Each part is calculated as 7 cm from the total length of AB (28 cm), resulting in AC being 21 cm and CB being 7 cm. The correct answer is A .

Step-by-step explanation:

The question involves finding the lengths of line segments AC and CB when a point C divides the line segment AB, which is 28 cm long, into a ratio of 3 to 1. To solve this, we can use the concept of proportionality. The sum of the ratios (3 + 1) gives us 4 parts in total. As AB is 28 cm, each part is 28 cm ÷ 4 which equals to 7 cm. Therefore, segment AC, which is 3 parts, is 3 × 7 cm = 21 cm and segment CB, which is 1 part, is 7 cm.

Summarizing:

  • Total length of AB = 28 cm
  • Ratio of division by point C = 3:1
  • Length of each part = Total length ÷ Sum of ratios
  • Length of AC = 3 × (Length of each part)
  • Length of CB = 1 × (Length of each part)

Thus, the correct answer is AC = 21 cm and CB = 7 cm.

To find the lengths of line segments AC and CB, we can use the concept of ratios. Since AB is divided into the ratio 3 to 1, AC would be three-fourths (3/4) of AB and CB would be one-fourth (1/4) of AB.

Since AB = 28 cm, AC = (3/4) * 28 cm = 21 cm and CB = (1/4) * 28 cm = 7 cm.

Therefore, the correct answer is option a) AC=21 cm, CB=7 cm.

User Bryan Massoth
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