Question

The electric field in a particular thundercloud is 3.1 ✕ 105 N/C. What is the acceleration (in m/s2) of an electron in this field? (Enter the magnitude.)

Answer 1

The acceleration of an electron in the given electric field is approximately 1.94 × 10^24 m/s^2.

Step-by-step explanation:

The electric field in a particular thundercloud is 3.1 × 105 N/C. To find the acceleration of an electron in this field, we can use the formula:

acceleration = electric field / electron's charge

Given that the charge of an electron is 1.6 × 10-19 C, we can substitute the values into the formula:

acceleration = 3.1 × 105 N/C / 1.6 × 10-19 C

Simplifying the expression, we get:

acceleration ≈ 1.94 × 1024 m/s2