Final answer:
The volume occupied by 1.20 x 10^3 g of lithium is 2264.15 cm^3. The volume occupied by 1.20 x 10³ g of lithium is approximately 2264.15 cm³, calculated using the formula volume = mass/density with the given density of 0.530 g/cm³.
Step-by-step explanation:
To find the volume occupied by 1.20 x 10^3 g of lithium, we can use the formula:
Volume = Mass / Density
Substituting the given values:
Volume = 1.20 x 10^3 g / 0.530 g/cm^3
Volume = 2264.15 cm^3
Therefore, the volume occupied by 1.20 x 10^3 g of lithium is 2264.15 cm^3.
The volume occupied by 1.20 x 10³ g of lithium is approximately 2264.15 cm³, calculated using the formula volume = mass/density with the given density of 0.530 g/cm³.
To calculate the volume occupied by a certain mass of lithium, we use the formula for density, which is density = mass/volume. Given the density of lithium as 0.530 g/cm³, and the mass of lithium as 1.20 x 10³ g, we can rearrange the formula to solve for volume: volume = mass/density.
Therefore, the volume occupied by 1.20 x 10³ g of lithium is:
volume = (1.20 x 10³ g) / (0.530 g/cm³) = 2264.15 cm³.
This calculation shows that the volume of lithium that 1.20 x 10³ g occupies is approximately 2264.15 cm³.