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The concentration of carbon monoxide in an urban apartment is 48 g/m^3. What mass of carbon monoxide in grams is present in a room measuring 10.0x10.5x20.5 ft?

User Ibebbs
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Final answer:

To calculate the mass of carbon monoxide in the room, dimensions are first converted to meters, the volume is then determined, and finally, the mass is found by multiplying the volume by the given concentration, resulting in approximately 2918.736 grams of carbon monoxide.

Step-by-step explanation:

The question asks for the calculation of the mass of carbon monoxide in a room with given dimensions. To find the mass, we need to first convert the room's measurements from feet to meters and then calculate the volume of the room. The concentration of carbon monoxide is given in grams per cubic meter (g/m3), so by multiplying the concentration by the volume of the room, we can determine the mass of carbon monoxide inside it.

First, we convert the room dimensions from feet to meters:

  • 10.0 ft = 3.048 meters
  • 10.5 ft = 3.2004 meters
  • 20.5 ft = 6.2484 meters

Next, we calculate the volume in cubic meters:

Volume = length × width × height = 3.048 m × 3.2004 m × 6.2484 m = 60.807 cubic meters (m3).

Now, we calculate the mass of carbon monoxide:

Mass = concentration × volume = 48 g/m3 × 60.807 m3 = 2918.736 grams.

Therefore, the mass of carbon monoxide present in the room is approximately 2918.736 grams.

User DKMudrechenko
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