Final answer:
To find the value of q in the equation qx²+3x+2=4 when x=5, substitute x=5 into the equation and solve for q by simplifying and isolating q on one side of the equation.
Step-by-step explanation:
Quadratic equations are the polynomial equations of degree 2 in one variable of type f(x) = ax2 + bx + c = 0 where a, b, c, ∈ R and a ≠ 0. It is the general form of a quadratic equation where 'a' is called the leading coefficient and 'c' is called the absolute term of f (x).
The quadratic formula helps us solve any quadratic equation. First, we bring the equation to the form ax²+bx+c=0, where a, b, and c are coefficients. Then, we plug these coefficients in the formula: (-b±√(b²-4ac))/(2a) .
To find the value of q in the equation qx²+3x+2=4 when x=5, we can substitute x=5 into the equation and solve for q.
Let's substitute x=5 into the equation: q(5)²+3(5)+2=4
This simplifies to 25q + 15 + 2 = 4
Combining like terms, we have 25q + 17 = 4
Subtracting 17 from both sides, we get 25q = -13
Finally, dividing both sides by 25, we find that q = -13/25