Final answer:
To determine the weight of a 3.5 mole sample of Fluorine, the molar mass of Fluorine (38.00 g/mol) is used as a conversion factor, resulting in the sample weighing 133.00 grams.
Step-by-step explanation:
The question asks how much a 3.5 mole sample of Fluorine weighs. To find the weight of the sample, we need to use the molar mass of Fluorine as a conversion factor. The molar mass of a substance, which is expressed in grams per mole (g/mol), relates the number of moles to the mass in grams. First, identify the molar mass of Fluorine (F2), which is approximately 38.00 g/mol (each Fluorine atom has an atomic mass of roughly 19.00 amu, and there are two atoms in a fluorine molecule).
Using this molar mass, the conversion from moles to grams is straightforward: 3.5 moles × 38.00 g/mol = 133.00 grams. This shows that a 3.5 mole sample of Fluorine would weigh 133.00 grams. The number of significant figures in the final answer is determined by the number of significant figures in the given quantity, which here is three.