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A flower pot falls from a window ledge 25 meters above the ground. What is the magnitude of the flower pot's acceleration as it travels toward the sidewalk?

User Okliv
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Final answer:

The flower pot will accelerate towards the ground at a constant rate of 9.8 m/s², which is the acceleration due to gravity on Earth.

Step-by-step explanation:

The magnitude of the flower pot's acceleration as it travels toward the sidewalk is determined by the force of gravity. On Earth, the acceleration due to gravity is a constant 9.8 m/s², regardless of the mass of the falling object. Therefore, the flower pot would accelerate at 9.8 m/s² towards the ground. It's important to note that this is a case of free fall, where the only force acting on the object is gravity, and air resistance is negligible.

User Ashish Sajwan
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