Question

When making a long distance call from a certain pay phone, the first three minutes of a call cost $2.35. After that, each additional minute or portion of a minute of that call costs $0.35. Use an inequality to find the maximum number of minutes one can call long distance for $3.05.

A. at most 2 minutes
B. at most 1 minutes
C. at most 5 minutes
D. at most 9 minutes

Answer 1

A. at most 2 minutes. To find the maximum number of minutes one can call long distance for $3.05, set up the inequality 0.70 <= 0.35m and solve for 'm'. The maximum number of minutes is 2 minutes.

Step-by-step explanation:

To find the maximum number of minutes one can call long distance for $3.05, we need to set up an inequality. Let's assume the maximum number of minutes as 'm'. The cost for the first three minutes is $2.35, so the cost for the remaining minutes is $3.05 - $2.35 = $0.70. Since each additional minute costs $0.35, we can set up the inequality: 0.70 <= 0.35m. Now we can solve for 'm' by dividing both sides of the inequality by 0.35: m <= 2. Therefore, the maximum number of minutes one can call long distance for $3.05 is 2 minutes.