Final answer:
The question involves calculating the time it takes for two objects to hit the ground when dropped from a height, which is a part of understanding projectile motion in Physics. Using kinematic equations, we can find the difference in time taken by two objects to reach the ground when one is dropped without initial velocity and the other with an initial velocity.
Step-by-step explanation:
Understanding Projectile Motion and Its Applications
To address the original question, we need to clarify two scenarios that seem relevant: (1) an object being dropped from a height and (2) an object being projected upward. The concept we are dealing with here is projectile motion, particularly the free fall and vertical launch components.
If we consider the provided example, we can discuss a scenario where two identical objects are dropped from a building: Object 1 is dropped with no initial velocity, while Object 2 is thrown down with an initial velocity. To calculate the difference in time it takes for each object to hit the ground, we use the kinematic equations for uniformly accelerated motion (gravity being the acceleration).
Let's use this scenario to calculate the time it takes for two objects dropped from 50.0 m high. Object 1 (initial velocity of 0 m/s) and Object 2 (initial velocity of 13.0 m/s) both accelerate at 9.81 m/s2 due to gravity:
- Use the equation d = v_i*t + (1/2)*a*t^2 to solve for the time (t) it takes for each object to reach the ground.
- Subtract the time it took for Object 1 to fall from the time it took for Object 2.
- The result will be the difference in time, rounded to the nearest tenth of a second.
Carrying out these calculations will give us the insight needed to understand the original question. Please note that air resistance is typically ignored in these elementary physics problems.