Final answer:
To check if a given integer 'x' is present in a list of integers, you can use the 'in' operator. Use the provided code to implement the functionality.
Step-by-step explanation:
To check if a given integer 'x' is present in a list of integers, you can use the 'in' operator. Here's the code you can use:
def check_x_in_list(int_list, x):
if x in int_list:
return 'yes'
else:
return 'no'
list_of_integers = [1, 2, 3, 4, 5]
x = 3
result = check_x_in_list(list_of_integers, x)
print(result)
In this example, the function 'check_x_in_list' accepts the list of integers 'int_list' and the integer 'x' as input. It checks if 'x' is present in the list using the 'in' operator and returns 'yes' or 'no' accordingly.
To check if an integer x is present in a list of integers, iterate through the list and compare each element with x. If a match is found, print 'yes', otherwise print 'no'. This logic can be easily implemented in various programming languages.
If you are looking to check if an integer x is present in a given list of integers, you can write a simple program in many programming languages such as Python, Java, C++, etc. The process involves iterating through the list and checking each element to see if it matches x. If a match is found, the program will output 'yes', otherwise it will output 'no'. Here's an example of how you might write such a program in Python:
integers = [1, 2, 3, 4, 5]
x = 3
if x in integers:
print('yes')
else:
print('no')
This snippet will print 'yes' because 3 is present in the list integers.