Final answer:
The specific heat capacity of ethanol is 0.247 J/g°C.
Step-by-step explanation:
The specific heat capacity of a substance is the amount of heat required to raise the temperature of 1 gram of the substance by 1 degree Celsius or 1 Kelvin. In this case, we are given that 221.4 Joules of heat is needed to heat 30 grams of ethanol from 150°C to 180°C. To calculate the specific heat capacity, we can use the formula:
specific heat capacity = (heat energy)/(mass x temperature change)
Plugging in the given values:
specific heat capacity = (221.4 J)/(30 g x (180°C - 150°C)) = 221.4 J / (30 g x 30°C)
solving this equation gives us a specific heat capacity of 0.247 J/g°C (rounded to 3 decimal places).