Question

difference between two molar specific heat of gas 8000J/kgk. if the ratio of two specific heat is 1.65,calculate the two molar specific heat.

Answer 1

The molar specific heats of the gas are calculated by solving two simultaneous equations derived from the given difference in specific heats and their ratio. The two molar specific heats are found to be approximately Cp = 20307.69 J/kgK and Cv = 12307.69 J/kgK.

Step-by-step explanation:

The question asks for the calculation of molar specific heats of a gas when given the difference between two molar specific heats and their ratio. Given that the difference between the molar specific heats (Cp - Cv) is 8000 J/kgK and the ratio of the specific heats (γ = Cp/Cv) is 1.65, we can set up the following equations:

• Cp - Cv = 8000 J/kgK
• Cp/Cv = 1.65

We can solve these two equations simultaneously to find the values of Cp and Cv. Let's express Cp in terms of Cv using the second equation: Cp = 1.65 * Cv. Substituting this into the first equation gives us:

1.65 * Cv - Cv = 8000 J/kgK

0.65 * Cv = 8000 J/kgK

Now we can solve for Cv:

Cv = 8000 J/kgK / 0.65

Cv = 12307.69 J/kgK (approximately)

Now we can calculate Cp using the ratio again:

Cp = 1.65 * Cv

Cp = 1.65 * 12307.69 J/kgK

Cp = 20307.69 J/kgK (approximately)

So, the two molar specific heats of the gas are Cp = 20307.69 J/kgK and Cv = 12307.69 J/kgK.